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30_ch 08 Mechanical Design budynas_SM_ch08

# 30_ch 08 Mechanical Design budynas_SM_ch08 - von Mises...

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Chapter 8 233 Use 1 3 4 " bolts L T = 2 D + 1 4 = 2(0 . 5) + 0 . 25 = 1 . 25 in l d = 1 . 75 1 . 25 = 0 . 5 l t = 1 . 095 0 . 5 = 0 . 595 A d = π (0 . 5) 2 4 = 0 . 1963 in 2 A t = 0 . 1419 in k b = A d A t E A d l t + A t l d = 0 . 1963(0 . 1419)(30) 0 . 1963(0 . 595) + 0 . 1419(0 . 5) = 4 . 451 Mlbf/in Two identical frusta A = 0 . 787 15, B = 0 . 628 73 k m = Ed A exp 0 . 628 73 d L G = 30(0 . 5)(0 . 787 15) exp 0 . 628 73 0 . 5 1 . 095 k m = 15 . 733 Mlbf/in C = 4 . 451 4 . 451 + 15 . 733 = 0 . 2205 S p = 85 kpsi F i = 0 . 75(0 . 1419)(85) = 9 . 046 kip σ i = 0 . 75(85) = 63 . 75 kpsi σ b = C P + F i A t = 0 . 2205(1 . 286) + 9 . 046 0 . 1419 = 65 . 75 kpsi τ s = F s A s = 3 0 . 1963 = 15 . 28 kpsi
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Unformatted text preview: von Mises stress σ ± = ( σ 2 b + 3 τ 2 s ) 1 / 2 = [65 . 74 2 + 3(15 . 28 2 )] 1 / 2 = 70 . 87 kpsi Stress margin m = S p − σ ± = 85 − 70 . 87 = 14 . 1 kpsi Ans. 0.75" 0.5" t ± 0.5475"...
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