32_ch 03 Mechanical Design budynas_SM_ch03

32_ch 03 Mechanical Design budynas_SM_ch03 -...

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3-30 R 1 = c l F M = c l Fx 0 x a σ = 6 M bh 2 = 6( c / l ) 2 h = ± 6 cFx bl σ max 0 x a Ans. 3-31 From Prob. 3-30, R 1 = c l F = V ,0 x a τ max = 3 2 V = 3 2 ( c / l ) F h = 3 2 Fc lb τ max Ans . From Prob. 3-30 = ± 6 Fcx σ max sub in x = e and equate to h above 3 2 τ max = ± 6 Fce σ max e = 3 8 σ max τ 2 max Ans. 3-32 R 1 = b l F M = b l σ max = 32 M π d 3 = 32 π d 3 b l d = ² 32 π bFx l σ max ³ 1 / 3 0 x a Ans. 3-33 Square: A m = ( b t ) 2 T sq = 2 A m t τ all = 2( b t ) 2 t τ all Round:
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This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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