This preview shows
page 1. Sign up
to
Chapter 17
451
(b)
Try
m
=
4 strands
F
t
=
8
4
+
3
.
2
d
2
1
+
2
32
.
2
=
2
.
12
+
3
.
4
d
2
kip
F
f
=
12
.
1
d
kip
n
=
12
.
1
d
2
.
12
+
3
.
4
d
2
Comparing tables, multiple ropes supporting the load increases the factor of safety,
and reduces the corresponding wire rope diameter, a useful perspective.
17-32
n
=
ad
b
/
m
+
cd
2
dn
dd
=
(
b
/
m
+
cd
2
)
a
−
ad
(2
cd
)
(
b
/
m
+
cd
2
)
2
=
0
From which
d
*
=
b
mc
Ans.
n
*
=
a
√
b
/
(
mc
)
(
b
/
m
)
+
c
[
b
/
(
mc
)]
=
a
2
m
bc
Ans.
These results agree closely with Prob. 17-31 solution. The small differences are due to
rounding in Prob. 17-31.
This is the end of the preview.
Sign up
to
access the rest of the document.
- Fall '11
- Shingley
- Broadway – Lafayette Street, Wire, corresponding wire rope
-
Click to edit the document details
