{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

34_ch 04 Mechanical Design budynas_SM_ch04

34_ch 04 Mechanical Design budynas_SM_ch04 - θ R d θ = π...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 4 103 4-66 A : Dummy load Q is applied at A . Bending in AB due only to Q which is zero. M = P R sin θ + QR (1 + sin θ ), M Q = R (1 + sin θ ), 0 θ π 2 ( δ A ) V = U Q Q = 0 = 1 E I π/ 2 0 ( P R sin θ )[ R (1 + sin θ )] R d θ = P R 3 E I cos θ + θ 2 sin 2 θ 4 π/ 2 0 = P R 3 E I 1 + π 4 = π + 4 4 P R 3 E I Ans. B : M = P R sin θ , M P = R sin θ ( δ B ) V = U P = 1 E I π/ 2 0 ( P R sin θ )( R sin θ ) R d
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: θ ) R d θ = π 4 P R 3 E I Ans. 4-67 M = P R sin θ , ∂ M ∂ P = R sin θ < θ < π 2 T = P R (1 − cos θ ), ∂ T ∂ P = R (1 − cos θ ) A R z x y M T 200 N ± 200 N P Q B A C ±...
View Full Document

{[ snackBarMessage ]}