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38_ch 04 Mechanical Design budynas_SM_ch04

# 38_ch 04 Mechanical Design budynas_SM_ch04 -...

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Chapter 4 107 But M /∂ M A = 1 . Therefore π/ 2 0 M d θ = π/ 2 0 M A F R 2 (1 cos θ ) d θ = 0 Since this term is zero, we have M A = F R 2 1 2 π Substituting into Eq. (1) M = F R 2 cos θ 2 π The maximum occurs at B where θ = π/ 2 . It is M B = − F R π Ans. 4-72 For one quadrant M = F R 2 cos θ 2 π ; M F = R 2 cos θ 2 π δ = U F = 4 π/ 2 0 M E I M F R d θ = F R 3 E I π/ 2 0 cos θ 2
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