45_ch 04 Mechanical Design budynas_SM_ch04

# 45_ch 04 Mechanical Design budynas_SM_ch04 - 2 ) g W 1 / 2...

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114 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design y max = W 1 k ± 2 hk W 1 + W 2 + 1 ² 1 / 2 + W 1 k Ans. F max = ky max + W 2 = W 1 ± 2 hk W 1 + W 2 + 1 ² 1 / 2 + W 1 + W 2 Ans. 4-83 Assume x > y to get a free-body diagram. Then W g ¨ y = k 1 ( x y ) k 2 y A particular solution for x = a is y = k 1 a k 1 + k 2 Then the complementary plus the particular solution is y = A cos ω t + B sin ω t + k 1 a k 1 + k 2 where ω = ³ ( k 1 + k
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Unformatted text preview: 2 ) g W 1 / 2 At t = 0, y = 0, and y = 0. Therefore B = 0 and A = k 1 a k 1 + k 2 Substituting, y = k 1 a k 1 + k 2 (1 cos t ) Since y is maximum when the cosine is 1 y max = 2 k 1 a k 1 + k 2 Ans . k 1 ( x y ) k 2 y W y x...
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## This note was uploaded on 12/13/2011 for the course EML 3013 taught by Professor Shingley during the Fall '11 term at UNF.

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