47_ch 03 Mechanical Design budynas_SM_ch03

# 47_ch 03 Mechanical Design budynas_SM_ch03 - 3-68 δ = 1...

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60 Solutions Manual • Instructor’s Solution Manual to Accompany Mechanical Engineering Design 3-64 δ max = 1 2 (40 . 059 40 . 000) = 0 . 0295 mm Ans. δ min = 1 2 (40 . 043 40 . 025) = 0 . 009 mm Ans. Eq. (2) p max = 114 . 5MPa, p min = 34 . 9 MPa Ans. 3-65 δ max = 1 2 (1 . 5023 1 . 5000) = 0 . 001 15 in Ans. δ min = 1 2 (1 . 5017 1 . 5010) = 0 . 000 35 in Ans. Eq. (1) p max = 17 250 psi p min = 5250 psi Ans. 3-66 δ max = 1 2 (40 . 076 40 . 000) = 0 . 038 mm Ans. δ min = 1 2 (40 . 060 40 . 025) = 0 . 0175 mm Ans. Eq. (2) p max = 147 . 5MPa p min = 67 . 9 MPa Ans. 3-67 δ max = 1 2 (1 . 5030 1 . 500) = 0 . 0015 in Ans. δ min = 1 2 (1 . 5024 1 . 5010) = 0 . 0007 in Ans. Eq. (1) p max = 22 500 psi p min = 10 500 psi Ans.
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Unformatted text preview: 3-68 δ = 1 2 (1 . 002 − 1 . 000) = . 001 in r i = 0, R = . 5 in, r o = 1 in ν = . 292, E = 30 Mpsi Eq. (3-57) p = 30(10 6 )(0 . 001) . 5 3 ± (1 2 − . 5 2 )(0 . 5 2 − 0) 2(1 2 − 0) ² = 2 . 25(10 4 ) psi Ans. Eq. (3-50) for outer member at r i = . 5 in ( σ t ) o = . 5 2 (2 . 25)(10 4 ) 1 2 − . 5 2 ³ 1 + 1 2 . 5 2 ´ = 37 500 psi Ans....
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