HW4_STA5166_old_complete

# HW4_STA5166_old_complete - Problem 4.1 a What kind of an...

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Problem 4.1 a) What kind of an experimental design is this? Randomized Block Design b) Make a graphical analysis and an ANOVA. Analyzing each of the paint suppliers, the mean is different for each of them as illustrated above.

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ANOVA output > summary(fit1) Df Sum Sq Mean Sq F value Pr(>F) supplier 3 665.13 221.71 20.387 1.503e-05 *** site 5 568.71 113.74 10.459 0.0001808 *** Residuals 15 163.13 10.88 --- Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1 55 60 65 70 75 -2 0 2 4 6 fit1\$fitted.values fit1\$residuals Analyzing the residuals, assume no effect since no pattern and wide spread. CODE >Prob4.1=read.table(file="E:/FSU-FALL07-School/Fall07-school/STA5166/BHH2- Data/prb0401.dat", header=TRUE) >Prob4.1 > par(mfrow=c(1,1)) >plot(Prob4.1\$supplier, Prob4.1\$y) >fit1= aov(y~supplier + factor(site), data=Prob4.1) >fit2= aov(y~supplier, data=Prob4.1) >summary(fit1) >attributes(fit1) >par(mfrow=c(1,1)) >plot(fit1\$fitted.values, fit1\$residuals) ##LOAD BBH2 package >par(mfrow = c(1, 1), cex = 0.7) >anovaPlot(fit1, main = "Anova plot: problem 4.1",labels = TRUE, cex.lab = 0.6 )
c) Obtain confidence limits for the supplier averages Using R General Linear Hypotheses Multiple Comparisons of Means: Tukey Contrasts Linear Hypotheses: Estimate GS - FD == 0 9.8333 L - FD == 0 -2.0000 ZK - FD == 0 9.0000 L - GS == 0 -11.8333 ZK - GS == 0 -0.8333 ZK - L == 0 11.0000 Simultaneous Confidence Intervals for General Linear Hypotheses Multiple Comparisons of Means: Tukey Contrasts Fit: aov(formula = y ~ supplier, data = Prob4.1) Estimated Quantile = 2.799 Linear Hypotheses: Estimate lwr upr GS - FD == 0 9.83333 0.05797 19.60869 L - FD == 0 -2.00000 -11.77536 7.77536 ZK - FD == 0 9.00000 -0.77536 18.77536 L - GS == 0 -11.83333 -21.60869 -2.05797 ZK - GS == 0 -0.83333 -10.60869 8.94203 ZK - L == 0 11.00000 1.22464 20.77536 95% family-wise confidence level Simultaneous Tests for General Linear Hypotheses Multiple Comparisons of Means: Tukey Contrasts Fit: aov(formula = y ~ supplier, data = Prob4.1) Linear Hypotheses: Estimate Std. Error t value p value GS - FD == 0 9.8333 3.4925 2.816 0.0641 . L - FD == 0

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## This note was uploaded on 12/14/2011 for the course STAT 5166 taught by Professor Staff during the Fall '11 term at FSU.

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HW4_STA5166_old_complete - Problem 4.1 a What kind of an...

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