bmgt452 problem set #1

# bmgt452 problem set #1 - Tatiana Nemirovsky Liza Levin...

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Tatiana Nemirovsky Liza Levin Problem Set 1 1. Mean= 6.947 Median= 7 Mode= 8 Range= 8 Standard deviation= 2.198 Frequency Table: Total Total 19= 100% 2 1= 5.26% 3 1= 5.26% 4 1= 5.26% 5 1= 5.26% 6 2= 10.53% 7 4= 21.05% 8 5= 26.32% 9 2= 10.53% 10 2= 10.53% 2. Chi-square Test Step 1: i. Null Hypothesis: all premiums draw the same number of visitors to the showroom. ii. Alternative Hypothesis: all premiums draw different numbers of visitors to the showroom. Step 2: Pick a Test i. Chi Square Test Step 3: Significance Level = 0.05 Step 4: Calculation of Statistics i. 2 1 ( ) r i i i i O E E = - ii. Degrees of Freedom = df = r-1 = 4-1 = 3 iii. Critical Value = 9.48 Visitors Expected Stepladder 425 2250/4 =562.5 33.61 2 ( ) i i i O E E -

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\$50 gift card 610 562.5 4.01 Dinner 510 562.5 4.9 Flamingos 705 562.5 36.1 Total 2250 562.5 78.62 Step 5: Statistical Conclusion i. Because the calculated χ 2 = 78.62 is more than the critical value, we reject the null hypothesis and conclude that all premiums draw different numbers of visitors to the showroom. 3. T test Step 1: State the null and alternative hypothesis i. Null: boys and girls have the same mean time of playing with the kit ii. Alternative: boys and girls have different mean times of playing with the
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## This note was uploaded on 12/15/2011 for the course BMGT 452 taught by Professor Staff during the Fall '08 term at Maryland.

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bmgt452 problem set #1 - Tatiana Nemirovsky Liza Levin...

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