{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Economics Dynamics Problems 233

# Economics Dynamics Problems 233 - Discrete systems of...

This preview shows page 1. Sign up to view the full content.

Discrete systems of equations 217 In each of these instructions the last line is a check that undertaking the matrix multiplication does indeed lead to the Jordan form of the matrix. In each package we get the Jordan form J = ± 10 03 ² However, the transition matrix in each package on the face of it looks different. More speciFcally, Mathematica V = ± 11 ² Maple V = ³ 1 2 1 2 1 2 1 2 ´ Butthesearefundamentallythesame.Wenotedthiswhenderivingtheeigenvectors in the previous section. We arbitrarily chose values for v r 1 or v r 2 (along with the values associated with the eigenvalue s ). In Maple , consider the Frst column, which is the Frst eigenvector. Setting v r 2 = 1, means multiplying the Frst term by 2, which gives a value for v r 1 =− 1. Similarly, setting v s 1 = 1in Maple , converts v s 2 also to the value of unity. Hence, the two matrices are identical. In each case the last instruction veriFes that V 1 AV = J .
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online