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12
Physics and Measurement
P1.44
A typical raindrop is spherical and might have a radius of about 0.1 inch. Its volume is then
approximately
41
0
3
×
−
in
3
. Since 1 acre
43 560 ft
2
=
, the volume of water required to cover it to a
depth of 1 inch is
1 acre 1 inch
1 acre in
ft
1 acre
in
ft
6.3 10 in
63
af
a f
a
f
=⋅
F
H
G
I
K
J
F
H
G
I
K
J
≈×
43 560
144
1
2
2
2
.
The number of raindrops required is
n
==
×
×
=×
−
volume of water required
volume of a single drop
in
in
.
63 10
0
1 6 10
10
33
99
.
~.
*P1.45
Assume the tub measures 1.3 m by 0.5 m by 0.3 m. Onehalf of its volume is then
V
05 13
05
03
010
..
.
.
.
a
f
m
m
m
3
.
The mass of this volume of water is
mV
water
water
kg m
m
kg
kg
=
ρ
1 000
0 10
100
10
2
ej
e
j
.~
.
Pennies are now mostly zinc, but consider copper pennies filling 50% of the volume of the tub. The
mass of copper required is
copper
copper
kg m
m
kg
kg
=
8 920
0 10
892
10
3
e
j
.
P1.46
The typical person probably drinks 2 to 3 soft drinks daily. Perhaps half of these were in aluminum
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .
 Fall '11
 Staff
 Physics

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