Chapter 115*P1.57Consider one cubic meter of gold. Its mass from Table 1.5 is 19 300 kg. One atom of gold has massm027251973 27 10=×FHGIKJ=×−−u1.66 10kg1 ukgaf..So, the number of atoms in the cube isN=×−19 300590 102528kg3.27 10kgThe imagined cubical volume of each atom isd328291169 10=×−mm33.Sod−257 1010. m.P1.58ANAVVAVrrtotaldroptotaldropdroptotal4==FHGIKJ=FHGGIKJJejπ3324AVrtotaltotal32mmm=FHGIKJ=××FHGIKJ=−−3330 0 10200 1045065...P1.59One month is130243 6002 592 106modayh days hs×bgbgbgApplying units to the equation,Vtt=+150000800
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .