{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

17_Physics ProblemsTechnical Physics

# 17_Physics ProblemsTechnical Physics - Chapter 1 P1.64 V =...

This preview shows page 1. Sign up to view the full content.

Chapter 1 17 P1.64 (a) V = L 3 , A = L 2 , h = L V A h = L L L L 3 2 3 = = . Thus, the equation is dimensionally correct. (b) V R h R h Ah cylinder = = = π π 2 2 e j , where A R = π 2 V wh w h Ah rectangular object = = = A A a f , where A w = A P1.65 (a) The speed of rise may be found from v D = = = Vol rate of flow (Area: cm s cm s 3 cm a f a f π π 2 2 4 6 30 4 16 5 0 529 ) . . . . (b) Likewise, at a 1.35 cm diameter, v = = 16 5 11 5 1.35 4 2 . . cm s cm s 3 cm π a f . P1.66 (a) 1 cubic meter of water has a mass m V = = × = ρ 1 00 10 1 00 10 1 000 3 3 3 2 3 . kg cm . m cm m kg e je je j (b) As a rough calculation, we treat each item as if it were 100% water. cell: kg m m kg kidney: . kg cm cm kg fly: kg cm mm mm cm mm 3 3 3 2 m V R D m V R m D h = = F H G I K J = F H G I K J = F H G I K J × = × = = F H G I K J = × F H G I K J = = F H G I K J = × F H G I K J
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online