17_Physics ProblemsTechnical Physics

17_Physics ProblemsTechnical Physics - Chapter 1 P1.64 V =...

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Chapter 1 17 P1.64 (a) V = L 3 , A = L 2 , h = L VA h = LL 32 3 == . Thus, the equation is dimensionally correct. (b) VR h R h A h cylinder = ππ 22 ej , where AR = π 2 Vw h w h A h rectangular object = AA af , where Aw = A P1.65 (a) The speed of rise may be found from v D = Vol rate of flow (Area: cm s cm s 3 cm 4 630 4 16 5 0529 ) . . . . (b) Likewise, at a 1.35 cm diameter, v 16 5 11 5 1.35 4 2 . . cm s cm s 3 cm . P1.66 (a) 1 cubic meter of water has a mass mV × = ρ 1 00 10 1 00 10 1 000 333 2 3 . kg cm . m cm m kg e j e j (b) As a rough calculation, we treat each item as if it were 100% water. cell: kg m m kg kidney: . kg cm cm kg fly: kg cm mm mm cm mm 3 3 3 2 R D R mD h F H G I K J = F H G I K J = F H G I K J × F H G I K J F H G I K J = = F H G I K J F H G I K J −− ρρ 4 3 1
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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