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23_Physics ProblemsTechnical Physics

23_Physics ProblemsTechnical Physics - 24 P2.5 Motion in...

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24 Motion in One Dimension P2.5 (a) Let d represent the distance between A and B. Let t 1 be the time for which the walker has the higher speed in 5 00 1 . m s = d t . Let t 2 represent the longer time for the return trip in = − 3 00 2 . m s d t . Then the times are t d 1 5 00 = . m s b g and t d 2 3 00 = . m s b g . The average speed is: v d d d v d d d = = + + = = = Total distance Total time m s m s m s m s m s m s m s 2 2 2 2 5 00 3 00 8 00 15 0 2 2 15 0 8 00 3 75 . . . . . . . b g b g b g e j e j (b) She starts and finishes at the same point A. With total displacement = 0, average velocity = 0 . Section 2.2 Instantaneous Velocity and Speed P2.6 (a) At any time, t , the position is given by x t = 3 00 2 . m s 2 e j . Thus, at t i = 3 00 . s: x i = = 3 00 3 00 27 0 2 . . . m s s m 2 e j a f . (b) At t t f = + 3 00 . s : x t f = + 3 00 3 00 2 . . m s s 2 e j a f , or x t t f = + + 27 0 18 0 3 00 2 . . . m m s m s 2 b g e j a f . (c) The instantaneous velocity at
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