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28_Physics ProblemsTechnical Physics

28_Physics ProblemsTechnical Physics - Chapter 2(f Section...

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Chapter 2 29 (f) One way of phrasing the answer: The spacing of the successive positions would change with less regularity. Another way: The object would move with some combination of the kinds of motion shown in (a) through (e). Within one drawing, the accelerations vectors would vary in magnitude and direction. Section 2.5 One-Dimensional Motion with Constant Acceleration P2.19 From v v ax f i 2 2 2 = + , we have 10 97 10 0 2 220 3 2 . × = + ( ) m s m c h a , so that a = × 2 74 10 5 . m s 2 which is a g = × 2 79 10 4 . times . P2.20 (a) x x v v t f i i f = + 1 2 c h becomes 40 1 2 2 80 8 50 m m s s = + ( ) v i . . a f which yields v i = 6 61 . m s . (b) a v v t f i = = = 2 80 6 61 8 50 0 448 . . . . m s m s s m s 2 P2.21 Given v i = 12 0 . cm s when x t i = = ( ) 3 00 0 . cm , and at t = 2 00 . s, x f = 5 00 . cm, x x v t at f i i = + 1 2 2 : = ( )+ ( ) 5 00 3 00 12 0 2 00 1 2 2 00 2 . . . . . a = + 8 00 24 0 2 . . a a = = 32 0 2 16 0 . . cm s 2 . *P2.22 (a) Let i be the state of moving at 60 mi h and f be at rest v v a x x a a xf xi x f i x x 2 2 2 2 0 60 2 121 0 1 3 600 242 5 280
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