Chapter 229(f)One way of phrasing the answer: The spacing of the successive positions would changewith less regularity.Another way: The object would move with some combination of the kinds of motion shownin (a) through (e). Within one drawing, the accelerations vectors would vary in magnitudeand direction.Section 2.5One-Dimensional Motion with Constant AccelerationP2.19From vvaxfi222=+, we have 10 97100222032.×=+()msmcha, so that a=×2 74105.m s2which is ag=×2 79104.times .P2.20(a)xxvvtfiif−=+12chbecomes 40122 808 50mmss=+()vi..afwhich yields vi=6 61.m s .(b)avvtfi=−=−=−2 806 618 500 448....m sm ssm s2P2.21Given vi=12 0.cms when xti==()3 000.cm, and at t=2 00.s, xf=−5 00.cm,xxv tatfii−=+122: −−=()+()5 003 0012 0 2 00122 002.....a−=+8 0024 02..aa=−=−32 0216 0.. cm s2.*P2.22(a)Let ibe the state of moving at 60 mi h and fbe at restvvaxxaaxfxixfixx22220602121013 6002425 280
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