31_Physics ProblemsTechnical Physics

31_Physics ProblemsTechnical Physics - 32 *P2.26 Motion in...

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32 Motion in One Dimension *P2.26 The time for the Ford to slow down we find from xx vv t t x f i xi xf xi xf =+ + = + = + = 1 2 2 2250 71 5 0 699 di af m ms s . .. Its time to speed up is similarly t = () + = 2350 07 1 5 979 m s . The whole time it is moving at less than maximum speed is 699 500 218 ... . s s ++= . The Mercedes travels t f i xi xf + + = 1 2 0 1 2 71 5 71 5 21 8 1558 a f bg a f . s m while the Ford travels 250 350 600 += m m , to fall behind by 1 558 600 958 m m −= . P2.27 (a) v i = 100 m s, a = . m s 2 , a t fi so 0 100 5 = t , a 22 2 ch so 01 0 0 2 5 0 0 0 2 =( ) . x f . Thus x f = 1 000 m and t = 20 0 s . (b) At this acceleration the plane would overshoot the runway: No . P2.28 (a) Take t i = 0 at the bottom of the hill where x i = 0, v i = 30 0 . ms , a = 200 m s 2 . Use these values in the general equation v t a t fii =+ + 1 2 2 to find xt t f + 03 0 0 1 2 2 2 a f when t is in seconds t f = 30 0 2 . m. To find an equation for the velocity, use
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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