32_Physics ProblemsTechnical Physics

# 32_Physics ProblemsTechnical Physics - Chapter 2 P2.29 33...

This preview shows page 1. Sign up to view the full content.

Chapter 2 33 P2.29 In the simultaneous equations: vva t xx v v t xf xi x f i xi xf =+ R S | T | U V | W | 1 2 ch we have vv xf xi xi xf = () ( ) R S | T | U V | W | 560 420 62 4 1 2 .. ms s m s 2 . So substituting for v xi gives 62 4 1 2 56 0 4 20 4 20 . . m s s s 2 ( ) + ( ) xf xf 14 9 1 2 . s 2 ( ) v xf . Thus v xf = 310 . m s . P2.30 Take any two of the standard four equations, such as t v v t xf xi x f i xi xf R S | T | U V | W | 1 2 . Solve one for v xi , and substitute into the other: t xi xf x = v a t v t fi x fx x f = + 1 2 . Thus xxv t a t fix f x = 1 2 2 . Back in problem 29, 62 4 4 20 1 2 2 s m s s 2 =( ) −− v xf v xf = = 62 4 49 4 . m 4.20 s
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

Ask a homework question - tutors are online