39_Physics ProblemsTechnical Physics

39_Physics ProblemsTechnical Physics - 40 P2.46 Motion in...

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40 Motion in One Dimension P2.46 At any time t , the position of the ball released from rest is given by yh g t 1 2 1 2 = . At time t , the position of the ball thrown vertically upward is described by yv t g t i 2 2 1 2 = . The time at which the first ball has a position of y h 1 2 = is found from the first equation as h hg t 2 1 2 2 = , which yields t h g = . To require that the second ball have a position of y h 2 2 = at this time, use the second equation to obtain h v h g g h g i 2 1 2 = F H G I K J . This gives the required initial upward velocity of the second ball as vg h i = . P2.47 (a) vv g t fi = : v f = 0 when t = 300 . s , g = 980 m s 2 . Therefore, t i == ( ) = 9 80 3 00 29 4 .. . ms s 2 ch . (b) yy t =+ 1 2 −= = 1 2 29 4 3 00 441 . s m bg af *P2.48 (a) Consider the upward flight of the arrow. a y y y y yf yi y f i
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