41_Physics ProblemsTechnical Physics

41_Physics ProblemsTechnical Physics - 42 Motion in One...

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42 Motion in One Dimension Section 2.7 Kinematic Equations Derived from Calculus P2.53 (a) J da dt == constant da Jdt = aJ d tJ tc + z 1 but aa i = when t = 0 so ca i 1 = . Therefore, ta i =+ a dv dt dv adt va d t J t a d t J t c ii = = += + + zz bg 1 2 2 2 but vv i = when t = 0, so cv i 2 = and vJ t a t v + 1 2 2 v dx dt dx vdt xv d t J t v d t xJ t a t v t c xx i = = + + F H G I K J + + = 1 2 1 6 1 2 2 32 3 when t = 0, so cx i 3 = . Therefore, t a t v t x i + + 1 6 1 2 . (b) t a J t a J a t i 2 2 22 2 2 =+ = ++ af J t J a t 2 2 2 =+ + ch J J t 2 2 1 2 + F H G I K J
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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