44 Motion in One DimensionP2.56advdtv==−3 002., vi=1 50.m sSolving for v, dvdtv=−3 002.vdvdtvvttvvvvvttiii−==zz= −−+= −=−203 00113 003 0011....or When vvi=2, tvi==13 000 222..s.Additional Problems*P2.57The distance the car travels at constant velocity, v0, during the reaction time is ∆∆xvtra f10=. Thetime for the car to come to rest, from initial velocity v0, after the brakes are applied istvvavavafi2000=−=−=−and the distance traveled during this braking period is∆xvtvvtvvavafia f22200022022==+FHGIKJ=+FHGIKJ−FHGIKJ= −.Thus, the total distance traveled before coming to a stop issxxvtvarstop=+=−∆∆∆a fa f120022.*P2.58(a)If a car is a distance svtvarstop=−0022∆(See the solution to Problem 2.57) from theintersection of length siwhen the light turns yellow, the distance the car must travel beforethe light turns red is∆∆xs
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