45_Physics ProblemsTechnical Physics

45_Physics ProblemsTechnical Physics - 46 *P2.60 Motion in...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
46 Motion in One Dimension *P2.60 Average speed of every point on the train as the first car passes Liz: x t == 860 573 . . m 1.50 s ms . The train has this as its instantaneous speed halfway through the 1.50 s time. Similarly, halfway through the next 1.10 s, the speed of the train is 782 . . m 1.10 s = . The time required for the speed to change from 5.73 m/s to 7.82 m/s is 1 2 150 1 2 110 130 .. . s s s () + = so the acceleration is: a v t x x = 160 . . s 2 . P2.61 The rate of hair growth is a velocity and the rate of its increase is an acceleration. Then v xi = 104 . mm d and a x = F H G I K J 0132 . mm d w . The increase in the length of the hair (i.e., displacement) during a time of t 500 350 w d i s xv t a t x xi x =+ 1 2 1 2 0 132 35 0 5 00 2 . . . mm d d mm d w d w bg af a f or x = 48 0 . mm. P2.62 Let point 0 be at ground level and point 1 be at the end of the engine burn. Let point 2 be the highest point the rocket reaches and point 3 be just before
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online