47_Physics ProblemsTechnical Physics

47_Physics ProblemsTechnical Physics - 48 P2.65 Motion in...

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48 Motion in One Dimension P2.65 (a) Let x be the distance traveled at acceleration a until maximum speed v is reached. If this is achieved in time t 1 we can use the following three equations: xv v t i =+ 1 2 1 a f , 100 10 2 1 = t . af and vv a t i 1 . The first two give 100 10 2 1 2 10 2 1 2 200 20 4 11 1 =− F H G I K J F H G I K J = .. . . tv ta t a tt bg For Maggie: m s For Judy: m s 2 2 a a == 200 18 4 2 00 543 200 17 4 3 00 383 . . (b) va t = 1 Maggie: m s Judy: m s v v 5 43 2 00 10 9 3 83 3 00 11 5 . . a fa f (c) At the six-second mark xa t v t 1 2 600 1 2 1 . a f Maggie: m Judy: m x x = = 1 2 5 43 2 00 10 9 4 00 54 3 1 2 3 83 3 00 11 5 3 00 51 7 2 2 . . . . . . a fa f a fa f Maggie is ahead by 262 . m . P2.66
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