61_Physics ProblemsTechnical Physics

61_Physics ProblemsTechnical Physics - 62 P3.21 Vectors x =...

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62 Vectors P3.21 xr = cos θ and yr = sin , therefore: (a) x 12 8 150 .c o s , y 12 8 150 . sin , and xy , . . m bg ej =− + 11 1 6 40 ±± ij (b) x 330 600 o s. , y .s i n. , and cm =+ 165 286 . ± . ± (c) x 22 0 215 o s , y 22 0 215 . sin , and in 18 0 12 6 . ± . ± P3.22 xd == = cos cos 50 0 120 25 0 . m a faf yd = + sin sin . . ± . ± 50 0 120 43 3 25 0 43 3 m m m af a f a f di j *P3.23 (a) Her net x (east-west) displacement is −+ + = + 300 0 600 300 . . . blocks, while her net y (north- south) displacement is 0 4 00 0 4 00 ++ = + . . blocks. The magnitude of the resultant displacement is Rx y = net net a f a f 2 2 22 400 500 . . . blocks and the angle the resultant makes with the x -axis (eastward direction) is = F H G I K J ° −− tan . . tan . . 11 133 531 . The resultant displacement is then .. blocks at N of E ° . (b) The total distance traveled is 300 400 600 130 ... . ++= blocks . *P3.24
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