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63_Physics ProblemsTechnical Physics

63_Physics ProblemsTechnical Physics - 64 P3.29 Vectors We...

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64 Vectors P3.29 We have B R A = : A A R R x y x y = °= − = °= = °= = °= 150 75 0 150 120 130 140 35 0 115 140 35 0 80 3 cos120 cm cm cm cm . sin cos . sin . . Therefore, FIG. P3.29 B i j i j B = − − + = = + = = F H G I K J = ° 115 75 80 3 130 190 49 7 190 49 7 196 49 7 190 14 7 2 2 1 a f e j ± . ± ± . ± . tan . . . cm cm θ P3.30 A i j = − + 8 70 15 0 . ± . ± and B i j = 13 2 6 60 . ± . ± A B C + = 3 0 : 3 21 9 21 6 7 30 7 20 C B A i j C i j = = = . ± . ± . ± . ± or C x = 7 30 . cm ; C y = 7 20 . cm P3.31 (a) A B i j i j i j + = + − − = a f e j e j 3 2 4 2 6 ± ± ± ± ± ± (b) A B i j i j i j = − − − = + a f e j e j 3 2 4 4 2 ± ± ± ± ± ± (c) A B + = + = 2 6 6 32 2 2 . (d) A B = + = 4 2 4 47 2 2 . (e) θ
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