84_Physics ProblemsTechnical Physics

84_Physics ProblemsTechnical Physics - Chapter 4 Section...

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Chapter 4 85 Section 4.3 Projectile Motion P4.10 xv tv t x x y v tg t v t y xi i i yi i i == =− = = × cos cos . sin sin . . . θ 300 55 0 42 0 723 10 1 2 1 2 300 55 0 42 0 1 2 980 420 168 10 3 22 2 3 ms . . s m . s m 2 bg af a f a fa f ej a f P4.11 (a) The mug leaves the counter horizontally with a velocity v xi (say). If time t elapses before it hits the ground, then since there is no horizontal acceleration, t fx i = , i.e., t x vv f xi xi 140 . m a f In the same time it falls a distance of 0.860 m with acceleration downward of m s 2 . Then FIG. P4.11 yy v t a t fiy i y =+ + 1 2 2 : 00 8 6 0 1 2 2 =+ F H G I K J .. . m m s m 2 v xi . Thus, v xi 490 196 334 . ±ms
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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