94 Motion in Two Dimensions*P4.25The arrow’s flight time to the collision point istxxvfixi=−=°=1504550519mmssbgcos..The arrow’s altitude at the collision isyyvtatfiyiy=+ +=+°+ −=1204550519129847022ssm2afejsin.....(a)The required launch speed for the apple is given byvvayyvvyfyiyfiyiyi2222029847030 3−−−=di.m2(b)The time of flight of the apple is given byvvatttyfyiy=−=0 303310s2So the apple should be launched after the arrow by 209.s ss−=.*P4.26For the smallest impact angleθ=FHGIKJ−tan1vvyfxf,we want to minimize vyfand maximize xfxi=
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .