94_Physics ProblemsTechnical Physics

94_Physics ProblemsTechnical Physics - Chapter 4 Section...

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Chapter 4 95 Section 4.4 Uniform Circular Motion P4.27 a v r c == = 2 2 20 0 106 377 . . ms m 2 bg The mass is unnecessary information. P4.28 a v R = 2 , T 24 3 600 86 400 h s h s v R T × = 2 2 6 37 10 463 6 π (. m ) 86 400 s a = × = 463 637 10 00337 6 2 m m s directed toward the center of Earth 2 . .. P4.29 r = 0500 . m ; v r T a v R t = = = 2 20 5 0 0 10 47 10 5 10 47 05 219 60 0 2 2 . . . . m ms inwa rd s 200 rev 2 af a f P4.30 a v r c = 2 va r c = 3 9 8 9 45 16 7 ... ±ms ±m 2 ej Each revolution carries the astronaut over a distance of 2 2 945 594 ππ r m m . Then the rotation rate is 16 7 1 0281 rev 59.4 m rev s F H G I K J = . P4.31 (a) vr = ω At 8.00 rev s, v = 0 600 8 00 2 30 2 9 60 . m . rev s rad rev . m s
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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