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94_Physics ProblemsTechnical Physics

94_Physics ProblemsTechnical Physics - Chapter 4 Section...

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Chapter 4 95 Section 4.4 Uniform Circular Motion P4.27 a v r c = = = 2 2 20 0 1 06 377 . . m s m m s 2 b g The mass is unnecessary information. P4.28 a v R = 2 , T = = 24 3 600 86 400 h s h s b g v R T = = × = 2 2 6 37 10 463 6 π π ( . m) 86 400 s m s a = × = 463 6 37 10 0 033 7 6 2 m s m m s directed toward the center of Earth 2 b g . . . P4.29 r = 0 500 . m; v r T a v R t = = = = = = = 2 2 0 500 10 47 10 5 10 47 0 5 219 60 0 2 2 π π . . . . . . m m s m s m s inward s 200 rev 2 a f a f P4.30 a v r c = 2 v a r c = = = 3 9 8 9 45 16 7 . . . m s m m s 2 e j a f Each revolution carries the astronaut over a distance of 2 2 9 45 59 4 π π r = = . . m m a f . Then the rotation rate is 16 7 1 0 281 . . m s rev 59.4 m rev s F H G I K J = . P4.31 (a) v r = ω At 8.00 rev s, v = = = 0 600
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