Chapter 4105P4.56Using the range equation (Equation 4.14)Rvgii=22sin()θthe maximum range occurs when i=°45 , and has a value Rvgi=2. Given R, this yields vgRi=.If the boy uses the same speed to throw the ball vertically upward, thenRgty=−and ygRtgt22at any time, t.At the maximum height, vy=0, giving tRg=, and so the maximum height reached isRRggRgRRRmaxFHGIKJ=− =2222.P4.57Choose upward as the positive y-direction and leftward as thepositive x-direction. The vertical height of the stone when releasedfrom Aor Bisyi=+°=1 50 1 2030 02 10...m.msinaf(a)The equations of motion after release at AarevvgttyttxtyixiA−=−==sincos60 01 30 9 8060 00 750210 13049007502.msms.+..m. mejaf∆viBAvi30°30°1.20 mFIG. P4.57When y=0, t=−±+−=1 301 30
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