105_Physics ProblemsTechnical Physics

105_Physics ProblemsTechnical Physics - 106 P4.58 Motion in...

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106 Motion in Two Dimensions P4.58 The football travels a horizontal distance R v g ii == ° = 2 2 2 20 0 60 0 980 35 3 sin .s i n. . . θ bg af a f m. Time of flight of ball is t v g ° = 22 2 0 0 3 0 0 204 sin ( . )sin . . . s. FIG. P4.58 The receiver is x away from where the ball lands and x =−= 35 3 20 0 15 3 . . . m. To cover this distance in 2.04 s, he travels with a velocity v 15 3 750 . . . m s in the direction the ball was thrown . P4.59 (a) yg t =− 1 2 2 ; xv t i = Combine the equations eliminating t : x v i F H G I K J 1 2 2 . From this, x y g v i 2 2 2 = F H G I K J FIG. P4.59 thus y g i = = −−
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