126_Physics ProblemsTechnical Physics

126_Physics ProblemsTechnical Physics - 128 P5.25 The Laws...

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128 The Laws of Motion P5.25 After it leaves your hand, the block’s speed changes only because of one component of its weight: Fm a m g m a vv a xx fi =− ° = =+ sin . . 20 0 2 22 di Taking v f = 0, v i = 500 . m s, and ag = ° sin . 20 0 af gives 0 5 00 2 9 80 20 0 0 2 =( ) () ° .. s i n . ch x f or x f = ° = 25 0 2 9 80 20 0 373 . .s i n. . m. FIG. P5.25 P5.26 m 1 200 = . k g , m 2 600 = k g , θ 55 0 . (a) g T m a x = = sin and Tm gm a a mg mm −= = + = 11 21 12 357 sin . ms 2 (b) Tmag = 1 26 7 . N FIG. P5.26 (c) Since v i = va t f == ( ) = 714 . s 2 . *P5.27 We assume the vertical bar is in compression, pushing up on the pin with force A , and the tilted bar is in tension, exerting force
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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