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Chapter 5
129
P5.28
First, consider the 3.00 kg rising mass. The forces on it are
the tension,
T
, and its weight, 29.4 N. With the upward
direction as positive, the second law becomes
Fm
a
yy
∑
=
:
Ta
−
=
29 4
3 00
..
N
k
g
af
(1)
The forces on the falling 5.00 kg mass are its weight and
T
,
and its acceleration is the same as that of the rising mass.
Calling the positive direction down for this mass, we have
a
∑
=
: 49
5 00
k
g
−
=
.
(2)
FIG. P5.28
Equations (1) and (2) can be solved simultaneously by adding them:
TT
a
a
−
+
−
=+
29 4
49 0
3 00
5 00
.
.
N
N
kg
kg
(b)
This gives the acceleration as
a
==
19 6
245
.
.
N
8.00 kg
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .
 Fall '11
 Staff
 Physics, Force, Mass

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