Chapter 5129P5.28First, consider the 3.00 kg rising mass. The forces on it arethe tension, T, and its weight, 29.4 N. With the upwarddirection as positive, the second law becomesFmayy∑=: Ta−=29 43 00..N kgaf(1)The forces on the falling 5.00 kg mass are its weight and T,and its acceleration is the same as that of the rising mass.Calling the positive direction down for this mass, we havea∑=: 495 00kg−=.(2)FIG. P5.28Equations (1) and (2) can be solved simultaneously by adding them:TTaa−+−=+29 449 03 005 00..NNkgkg(b)This gives the acceleration asa==19 6245..N8.00 kg
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .