127_Physics ProblemsTechnical Physics

127_Physics ProblemsTechnical Physics - Chapter 5 P5.28...

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Chapter 5 129 P5.28 First, consider the 3.00 kg rising mass. The forces on it are the tension, T , and its weight, 29.4 N. With the upward direction as positive, the second law becomes Fm a yy = : Ta = 29 4 3 00 .. N k g af (1) The forces on the falling 5.00 kg mass are its weight and T , and its acceleration is the same as that of the rising mass. Calling the positive direction down for this mass, we have a = : 49 5 00 k g = . (2) FIG. P5.28 Equations (1) and (2) can be solved simultaneously by adding them: TT a a + =+ 29 4 49 0 3 00 5 00 . . N N kg kg (b) This gives the acceleration as a == 19 6 245 . . N 8.00 kg
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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