130 The Laws of Motion*P5.30Both blocks move with acceleration ammg=−+FHGIKJ21:a=−+FHGIKJ=7298544kgkg7 kg2 kgms22...(a)Take the upward direction as positive for m1.vvaxxxxxxfxixfifff2220242544057625440529=+−=−+−=−=dibgej:......mm below its initial level2(b)vvatvvxfxixxfxf=−+=...240180740sms upward2afP5.31Forces acting on 2.00 kg block:Tmgma−=11(1)Forces acting on 8.00 kg block:FTmax−=2(2)(a)Eliminate Tand solve for a:aFmgx=−+112aFmg
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .