132 The Laws of MotionP5.33First, we will compute the needed accelerations:102120008001503040120afBefore it starts to move:During the first 0.800 s:mssWhile moving at constant velocity:During the last 1.50 s:s22aavvtaatyyyfyiyyyfyi==−=−===−=−=−......FIG. P5.33Newton’s second law is: Fmayy∑=+−==+Sayy72 09 8072 070672 0...kgm skgN kg2bgej(a)When ay=0, S=706 N .(b)When ay=. ms2, S=814 N .(c)When ay=S=706 N .(d)When ay=−. ms2, S=648 N .P5.34(a)Pulley P1has acceleration a2.Since m1moves twicethe distance P1moves in the sametime, m1has twice the acceleration of P1, i.e., aa122=.(b)From the figure, and using
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .