135_Physics ProblemsTechnical Physics

135_Physics ProblemsTechnical Physics - Chapter 5 *P5.42...

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Chapter 5 137 *P5.42 First we find the coefficient of friction: Fn m g fnm g Fm a v v ax y ss xx f ix =+ = == + = 00 20 22 : : µµ −= = µ s i s i mg mv x v gx 2 2 2 2 2 88 2321 123 0981 ft s ft s ft 2 bg ej af . . n mg f n mg sin10° f mg cos10° FIG. P5.42 Now on the slope m g fn m g a m g m g mv x x v g y s s i i s ° = ° =− ° + ° = = °− ° = °− ° = 01 0 0 10 10 10 2 21 0 1 0 88 2 32 1 0 981 10 10 152 2 2 2 :c o s cos o s s i n cos sin .. c o s s i n . a f ft s ft s ft 2 P5.43 Tf a k = 500 . (for 5.00 kg mass) 900 gT a = (for 9.00 kg mass)
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