138_Physics ProblemsTechnical Physics

138_Physics ProblemsTechnical Physics - 140 *P5.48 The Laws...

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140 The Laws of Motion *P5.48 Since the board is in equilibrium, F x = 0 and we see that the normal forces must be the same on both sides of the board. Also, if the minimum normal forces (compression forces) are being applied, the board is on the verge of slipping and the friction force on each side is ff n ss == a f max μ . The board is also in equilibrium in the vertical direction, so Ff F yg = = 2 0, or f F g = 2 . The minimum compression force needed is then n f F s g s = () = μμ 2 95 5 72 0 . . N 20 .663 N. f n F = 95.5 N f n g FIG. P5.48 *P5.49 (a) nF fn F ° = =− sin cos .. , 15 75 25 0 67 97 0 259 24 67 0 094 N max a f µ For equilibrium:
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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