140_Physics ProblemsTechnical Physics

# 140_Physics ProblemsTechnical Physics - 142 P5.52 The Laws...

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142 The Laws of Motion P5.52 F a = m gives the object’s acceleration a i j a i j v = = = = F m t t d dt 8 00 4 00 4 00 2 00 . ± . ± . ± . ± . e j e j e j N 2.00 kg m s m s 2 3 Its velocity is d dt t dt t t v v i t t i v v v v a v i j v i j z z z = = = = = 0 4 00 2 00 4 00 1 00 0 0 2 . ± . ± . ± . ± . m s m s m s m s 2 3 2 3 e j e j e j e j (a) We require v = 15 0 . m s , v 2 225 = m s 2 2 16 0 1 00 225 1 00 16 0 225 0 16 0 16 0 4 225 2 00 9 00 3 00 2 4 4 2 2 2 . . . . . . . . . . t t t t t t m s m s m s s s s s 2 4 2 6 2 2 2 4 2 + = + = = ± = = a f a f Take r i = 0 at t = 0. The position is r v i j r i j = = =
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