141_Physics ProblemsTechnical Physics

141_Physics ProblemsTechnical Physics - Chapter 5 *P5.53...

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Chapter 5 143 *P5.53 (a) Situation A Fm a F nm g a g xx A s yy =+ = = :s i n :c o s µθ θ 0 0 Eliminate g = cos to solve for g As = sin cos μ af . n mg cos mg sin y x f s F A FIG. P5.53(a) (b) Situation B g a F g B s B = =− + = o s s i n i n c o s θµ θθ 0 0 Substitute g F B cos sin to find g F m g Bs s B cos cos sin sin ++ = 0 F mg B s s = + sin cos cos sin a f n mg cos mg sin y x f s F B FIG. P5.53(b) (c) F F A B ° = = °+ ° = 2 9 8 25 0 16 25 5 44 19 6 0 278 25 0 16 25 559 kg m s N N N 2 .s i n . c o s. .. cos . sin . a f Student A need exert less force. (d) F FF B AA = °+ ° = cos . sin . 25 0 38 25 1 07 Student B need exert less force. P5.54 18 2 3 4 N k g kg kg −= = Pa PQ a Qa bg Adding gives 18 9 k g = a so a = 200 2 . m s . FIG. P5.54 (b)
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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