146_Physics ProblemsTechnical Physics

146_Physics ProblemsTechnical Physics - 148 P5.61 The Laws...

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148 The Laws of Motion P5.61 F ma = For m 1 : T m a = 1 For m 2 : T m g = 2 0 Eliminating T , a m g m = 2 1 For all 3 blocks: FIG. P5.61 F M m m a M m m m g m = + + = + + F H G I K J 1 2 1 2 2 1 a f a f P5.62 t t x s s m 2 a f e j a f 2 0 0 0 1 02 1 04 0 0 100 1 53 2 34 1 0 200 2 01 4 04 0 0 350 2 64 6 97 0 0 500 3 30 10 89 0 750 3 75 14 06 1 00 . . . . . . . . . . . . . . . . . . FIG. P5.62 From x at = 1 2 2 the slope of a graph of x versus t 2 is 1 2 a , and a = × = = 2 2 0 071 4 0 143 slope m s m s 2 2 . . e j . From = a g sin θ , ′ =
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