147_Physics ProblemsTechnical Physics

147_Physics ProblemsTechnical Physics - Chapter 5 P5.63 a...

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Chapter 5 149 P5.63 (1) maA T a T m A 1 1 −=⇒ = + af (2) MA R T A T M x == = (3) ma mg T T m g a 22 2 =− = bg (a) Substitute the value for a from (1) into (3) and solve for T : FIG. P5.63 Tmg T m A = + F H G I K J L N M O Q P 2 1 . Substitute for A from (2): T m T M mg mM mM m m M = + F H G I K J L N M O Q P = ++ L N M O Q P 2 1 2 1 12 1 . (b) Solve (3) for a and substitute value of
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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