Chapter 6163*P6.11Fmgg===498392kgm sN2bgej..sin..θ==°1548 6m2 mr=2486132m mafcos..amvrTTxxab∑°+°=+=°=2248 648 64613210948 6165cos.cos..cos.kgm smNNbgayy∑=+°−°−=−=°=sin.sin...sin..48 648 6 39 2039 248 652 3NNN39.2 NT aTbforcesvacmotionFIG. P6.11(a)To solve simultaneously, we add the equations in Taand Tb:TTTTabab++−=+16552 3N N.Ta217108N2N(b)ba=−=−=16516510856 2NNN.*P6.12avrc=2. Let frepresent the rotation rate. Each revolution carries each bit of metal through distance2πr, so vrf=2andavrrfgc
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .