163_Physics ProblemsTechnical Physics

163_Physics ProblemsTechnical Physics - Chapter 6 b(a(b...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 6 165 P6.16 (a) a v r c == = 2 2 400 133 . . ms 12.0 m 2 bg (b) aaa ct =+ 22 a = 120 179 .. . a f a f 2 at an angle θ = F H G I K J tan . 1 48 0 a a c t inward FIG. P6.16 P6.17 F mv r mg n y + 2 But n = 0 at this minimum speed condition, so mv r mg v gr 2 980 100 313 =⇒ = = = . m 2 ej af . FIG. P6.17 P6.18 At the top of the vertical circle, Tm v R mg =− 2 or T = 0400 0500 0400 980 888 2 . . . . a f a f N P6.19 (a) v = 20 0 . ms , n = force of track on roller coaster, and R = 10 0 . m . F Mv R nM g 2 From this we find 10 m 15 m B A C FIG. P6.19 g Mv R n
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online