168_Physics ProblemsTechnical Physics

168_Physics ProblemsTechnical Physics - 170 *P6.30 Circular...

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170 Circular Motion and Other Applications of Newton’s Laws *P6.30 (a) The chunk is at radius r = + = 0 137 0 080 00542 .. . m m 4 m. Its speed is v r T == = 2 20 0 5 4 2 20 000 60 114 π . m s ms bg and its acceleration a v r g g c = × F H G I K J 2 2 5 54 114 238 10 98 243 10 m m s horizontally inward 2 2 2 . . . . (b) In the frame of the turning cone, the chunk feels a horizontally outward force of mv r 2 . In this frame its acceleration is up along the cone, at tan . . . 1 13 7 8 33 49 2 cm cm 2 af . Take the y axis perpendicular to the cone: n f mv r 2 49.2° a FIG. P6.30(b) Fm a n mv r n yy =+ ° = × ° = :s i n . .s i n . 2 35 49 2 0 2 10 2 38 10 49 2 360 kg m s N 2 ej e j (c) fn k = µ 06360 216 N N a mv r fm a a a xx x x x = ×× ° = × −− :c o s
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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