170 Circular Motion and Other Applications of Newton’s Laws*P6.30(a)The chunk is at radius r=+=0 1370 08000542...m m4m. Its speed isvrT===220054220 00060114π. msmsbgand its accelerationavrggc=×=×FHGIKJ22554114238 1098243 10mm s horizontally inward222....(b)In the frame of the turning cone, the chunk feels ahorizontally outward force of mvr2. In this frame itsacceleration is up along the cone, at tan...−−=°113 7 83349 2cmcm2af.Take the yaxis perpendicular to the cone:nfmvr249.2°aFIG. P6.30(b)Fma nmvrnyy∑=+−°=×°=−:sin..sin.23549 202 102 38 1049 2360kgm sN2ejej(c)fnk=µ06360216NNamvrfmaaaxxxxx∑−=××°−=×−−:cos
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .