169_Physics ProblemsTechnical Physics

169_Physics ProblemsTechnical Physics - Chapter 6 Section...

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Chapter 6 171 Section 6.4 Motion in the Presence of Resistive Forces P6.32 m = 80 0 . kg , v T = 50 0 . ms , mg DA v mg v T T =∴ = = ρ 2 2 22 0314 . k g m (a) At v = 30 0 ag m v =− = = 2 2 2 980 0314 300 80 0 627 . .. . . af a f m s downward 2 (b) At v = 50 0 . m s, terminal velocity has been reached. Fm g R Rm g y == − ⇒= = = 0 80 0 9 80 784 kg m s N directed up 2 bg ej (c) At v = 30 0 v 2 2 2 0 314 30 0 283 == a fa f N u pw a r d P6.33 (a) agb v When vv T = , a = 0 and gb v T = b g v T = The Styrofoam falls 1.50 m at constant speed v T in 5.00 s. Thus, v y t T = 150 0300 . . m 5.00 s ms Then b 32 7 1 . . . s 2 (b) At t = 0, v = 0 and . m s 2 down (c) When v = 0150 m s , v =− = = 327 490 1 ±ms ±s down P6.34 (a) = m V , A = 00201 m 2 , RA D v m g T = 1 = 2 2 air mV L N M O Q P = ρπ bead 3 gcm cm k g 0830 4 3 800 178 3 . Assuming a drag coefficient of
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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