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174_Physics ProblemsTechnical Physics

174_Physics ProblemsTechnical Physics - 176 P6.47 Circular...

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176 Circular Motion and Other Applications of Newton’s Laws P6.47 (a) At constant velocity F mg Cv T = = − + 0 2 v mg C T = − = − = 50 0 9 80 0 200 49 5 . . . . kg m s kg m m s 2 b g e j with chute closed and v T = − = 50 0 9 80 20 0 4 95 . . . . kg m s kg m m s b gb g with chute open. (b) We use time increments of 0.1 s for 0 10 < < t s, then 0.01 s for 10 12 s s < < t , and then 0.1 s again. time(s) height(m) velocity(m/s) 0 1000 0 1 995 –9.7 2 980 –18.6 4 929 –32.7 7 812 –43.7 10 674 –47.7 10.1 671 –16.7 10.3 669 –8.02 11 665 –5.09 12 659 –4.95 50 471 –4.95 100 224 –4.95 145 0 –4.95 6.48 (a) We use a time increment of 0.01 s.
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