179_Physics ProblemsTechnical Physics

179_Physics ProblemsTechnical Physics - Chapter 6 P6.57(a...

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Chapter 6 181 P6.57 (a) Since the centripetal acceleration of a person is downward (toward the axis of the earth), it is equivalent to the effect of a falling elevator. Therefore, ′ = F F mv r g g 2 or F F g g > (b) At the poles v = 0 and ′ = = = = F F mg g g 75 0 9 80 735 . . a f N down. FIG. P6.57 At the equator, ′ = = = F F ma g g c 735 75 0 0 033 7 732 N N N . . b g down. P6.58 (a) Since the object of mass m 2 is in equilibrium, F T m g y = = 2 0 or T m g = 2 . (b) The tension in the string provides the required centripetal acceleration of the puck. Thus, F T m g c = = 2 . (c) From F m v R c = 1 2 we have v RF m m m gR c = = F H G I K J 1 2 1 . P6.59 (a) v = F H G I K J = 300 88 0 60 0 440 mi h ft s mi h ft s b g . . At the lowest point, his seat exerts an upward force; therefore, his weight seems to increase.
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