187_Physics ProblemsTechnical Physics

187_Physics ProblemsTechnical Physics - Chapter 6 af 18.9...

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Chapter 6 189 P6.72 (a) td sm . . . . . . . . . . . . . . . . . . . . . . . . a f a f 100 200 300 400 500 600 700 800 900 10 0 11 0 12 0 13 0 14 0 15 0 16 0 17 0 18 0 19 0 20 0 488 18 9 42 1 73 8 112 154 199 246 296 347 399 452 505 558 611 664 717 770 823 876 (b) (s) (m) 900 800 700 600 500 400 300 200 100 0 0 2 4 6 8 10 12 14 16 18 20 t d (c) A straight line fits the points from t = 11 0 . s to 20.0 s quite precisely. Its slope is the terminal speed. v T == = slope m m 20.0 s s ms 876 399 11 0 53 0 . . *P6.73 vv k x i =− implies the acceleration is a dv dt k dx dt kv = 0 Then the total force is Fm amk v af The resistive force is opposite to the velocity: Fv km . ANSWERS TO EVEN PROBLEMS
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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