188_Physics ProblemsTechnical Physics

188_Physics - P6.58(a m g 2(b m g 2(c m m gR 2 1 F H G I K J(c 47 5 10 4 × m s 2 P6.32(a 6 27 m s downward 2(b 784 N up P6.60 62 2 rev min(c 283 N

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190 Circular Motion and Other Applications of Newton’s Laws P6.20 (a) 8.62 m; (b) Mg downward; P6.46 (a) 770 10 4 . × kg m; (b) 0.998 N; (c) 845 . m s 2 , Unless they are belted in, the riders will fall from the cars. (c) The ball reaches maximum height 49 m. Its flight lasts 6.3 s and its impact speed is 27 m s. P6.22 15 3 . m s Straight across the dashboard to the left P6.48 (a) see the solution; (b) 81.8 m; (c) 15.9 ° P6.24 0.527 ° P6.50 0835 . r e v s P6.26 (a) 1.41 h; (b) 17.1 P6.52 (a) mg mv R 2 ; (b) vg R = P6.28 µ k vt L ga t = + 2 2 af bg P6.54 (a) 263 . m s 2 ; (b) 201 m; (c) 17 7 . ms P6.56 (a) 106 N; (b) 0.396 P6.30 (a) 238 10 5 . × ms 2 horizontally inward 243 10 4 . g ; (b) 360 N inward perpendicular to the cone; P6.58 (a) mg
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Unformatted text preview: P6.58 (a) m g 2 ; (b) m g 2 ; (c) m m gR 2 1 F H G I K J (c) 47 5 10 4 . × m s 2 P6.32 (a) 6 27 . m s downward 2 ; (b) 784 N up; P6.60 62 2 . rev min (c) 283 N up P6.62 2 14 . rev min P6.34 (a) 53 8 . m s; (b) 148 m P6.64 (a) v R g = π ; (b) m g P6.36 1.40 P6.66 (a) 8.04 s; (b) 379 m s; (c) 1 19 . cm s; P6.38 − 0 212 . m s 2 (d) 9.55 cm P6.40 see the solution P6.68 (a) either 70.4 ° or 0 ° ; (b) 0 ° P6.42 36 5 . m s P6.70 (a) 78 3 . m s; (b) 11.1 s; (c) 121 m P6.44 (a) 0 980 . m s ; (b) see the solution P6.72 (a) and (b) see the solution; (c) 53 0 . m s...
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

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