202 Energy and Energy TransferP7.35vi=200. msµk=0100.KfxWKikf−+=∆other:1202mvfx−=∆122mvmg x=∆∆xvgik===2222 0 100 9 80204....msmbgafafSection 7.8Power*P7.36Pavkgm ssW==×=−WtKtmvtf∆∆∆223208750620221 10801.ejP7.37Power=Wt=mght70010 0800875N msWaf..P7.38A 1 300-kg car speeds up from rest to 55.0 mi/h =24.6 m/s in 15.0 s. The output work of the engine isequal to its final kinetic energy,121 30024 63902kgm skJbg.=with power =390 000104J15.0 sW~around 30 horsepower.P7.39(a)WK∑=∆, but ∆K=0 because he moves at constant speed. The skier rises a verticaldistance of 60 030 030 0.sin..m m°=. Thus,WWgin2kgm smJkJ=−==×=70098300206 102064....(b)The time to travel 60.0 m at a constant speed of 2.00 m/s is 30.0 s. Thus,inputJ30.0 sW hp×Wt∆6860 9194.P7.40(a)The distance moved upward in the first 3.00 s is∆yv
This is the end of the preview. Sign up
access the rest of the document.
This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .