203_Physics ProblemsTechnical Physics

203_Physics ProblemsTechnical Physics - Chapter 7 P7.47 b...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 7 205 P7.47 Concentration of Energy output =⋅ F H G I K J = 0600 600 1 24 0 .. . Jkgs tep kg step 1.50 m Jm bg b g F Fv v v = = = = 24 0 1 24 0 70 0 24 0 292 . Jm NmJ N W N ms af P P7.48 (a) Ai ⋅= ± cos A a fa f 1 α . But also, ± A x . Thus, AA x 1co s = or cos = A A x . Similarly, cos β = A A y and cos γ = A A z where A AAA xyz =+ + 222 . (b) cos cos cos 2 2 2 2 2 1 αβγ ++= F H G I K J + F H G I K J + F H G I K J == A A A A A A A A x y z P7.49 (a) xt t 200 3 . Therefore, v dx dt t Km v t t t + + =++ 16 0 0 1 2 1 2 4 00 1 6 00 2 00 24 0 72 0 2 22 2 24 . . ej e j J (b) a dv dt t 12 0 . 2 Fm a
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .

Ask a homework question - tutors are online