203_Physics ProblemsTechnical Physics

# 203_Physics ProblemsTechnical Physics - Chapter 7 P7.47 b...

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Chapter 7 205 P7.47 Concentration of Energy output = F H G I K J = 0 600 60 0 1 24 0 . . . J kg step kg step 1.50 m J m b gb g F Fv v v = = = = = 24 0 1 24 0 70 0 24 0 2 92 . . . . . J m N m J N W N m s b gb g a f P P7.48 (a) A i = ± cos A a fa f 1 α . But also, A i = ± A x . Thus, A A x a fa f 1 cos α = or cos α = A A x . Similarly, cos β = A A y and cos γ = A A z where A A A A x y z = + + 2 2 2 . (b) cos cos cos 2 2 2 2 2 2 2 2 1 α β γ + + = F H G I K J + F H G I K J + F H G I K J = = A A A A A A A A x y z P7.49 (a) x t t = + 2 00 3 . Therefore, v dx dt t K mv t t t = = + = = + = + + 1 6 00 1 2 1 2 4 00 1 6 00 2 00 24 0 72 0 2 2 2 2 2 4 . . . . . . a f e j e j J (b)
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