Chapter 8221*P8.8The energy of the car is Emvmgy=+122vmgd122sinθwhere dis the distance it has moved along the track.P==+dEdtmvdvdtmgvsin(a)When speed is constant,°=×mgvsin.sin.9502 20301 02 104kg 9.80 m sm sW2ejbg(b)dvdta−=220120183..mss2Maximum power is injected just before maximum speed is attained:=+××mva mgvsin...9502 20 1831 02 104kgm sm sW= 1.06 10 W24(c)At the top end,129502 209 801 250305 82 10226mvmgd+=+°FHGIKJ=×sin..sin.kg12mJ2*P8.9(a)Energy of the object-Earth system is conserved as the object moves between the releasepoint and the lowest point. We choose to measure heights from y=0 at the top end of thestring.KUgigf+:0122+mgymvmgyiff98230122298212292.cos.os.mmm2afaf−°=+−=−°=vvff(b)Choose the initial point at =°30 and the final point at 15 :03012152153029821
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This note was uploaded on 12/14/2011 for the course PHY 203 taught by Professor Staff during the Fall '11 term at Indiana State University .